If a ball is kicked at 35 degrees above the horizontal, what is the speed to barely clear the 3m tall goal post 60m away?
Range = Vo^2*sin(2A)/g = 60 m.
Vo^2*sin(70)/9.8 = 60
0.095887Vo^2 = 60
Vo^2 = 625.7
Vo = 25 m/s @ 35 Deg.
Vo^2*sin(70)/9.8 = 60
0.095887Vo^2 = 60
Vo^2 = 625.7
Vo = 25 m/s @ 35 Deg.