A truck has a maximum-load rating of 5 tons.It is going to be loaded with machine parts that each weigh 66 pounds 9 ounces.How many of the machine parts can be loaded into the truck without exceeding its maximum-load rating?
1 ton = 2,000 lbs.
5 tons = 10,000 lbs.
66 lbs., 9 ounces = 66.5625 lbs.
10,000 / 66.5625 = ?
Thanks
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To determine the number of machine parts that can be loaded into the truck without exceeding its maximum-load rating, we need to convert the maximum-load rating and the weight of each machine part into the same unit of measurement.
Given:
Maximum-load rating = 5 tons
Weight of each machine part = 66 pounds 9 ounces
First, let's convert the weight of each machine part to pounds:
Weight of each machine part = 66 pounds + 9 ounces
To convert 9 ounces to pounds, divide it by 16 since there are 16 ounces in a pound:
9 ounces / 16 = 0.5625 pounds
Now, add the pounds and the converted ounces:
Weight of each machine part = 66 pounds + 0.5625 pounds = 66.5625 pounds
Next, since the maximum-load rating is given in tons, we need to convert it to pounds. Since there are 2,000 pounds in a ton:
Maximum-load rating = 5 tons * 2,000 pounds/ton = 10,000 pounds
Now that we have both the weight of each machine part and the maximum-load rating in pounds, we can determine how many machine parts can be loaded into the truck:
Number of machine parts = Maximum-load rating / Weight of each machine part
Number of machine parts = 10,000 pounds / 66.5625 pounds ≈ 150.188
Since the number of machine parts must be a whole number, we round down to the nearest whole number:
Number of machine parts = 150
Therefore, the truck can be loaded with 150 machine parts without exceeding its maximum-load rating.