# pre-calculus

for the function f defined by:
(x)=3x^2+3x+2;find the following values.

a. f(-1)=
b. f(-x)=
c. -f(x)=
d. f(x+h)=

1. f(-1) = 2
f(-x) = 3x^2 - 3x + 2
-f(x) = -3x^2 - 3x - 2
f(x+h) = 3(x+h)^2 + 3(x+h) + 2

posted by Steve
2. Thank you so much for the help. I was off course.

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