A car is accelerating, from rest, at a rate of 6.74 m/s2. After 4.35 seconds, how far has the car gone?
To find how far the car has gone after 4.35 seconds, you can use the equation of motion:
\(d = v_0t + \frac{1}{2}at^2\)
Where:
d = distance traveled by the car
\(v_0\) = initial velocity (which is 0, since the car starts from rest)
t = time (4.35 seconds)
a = acceleration (6.74 m/s^2)
Substituting the given values into the equation:
\(d = 0 \times 4.35 + \frac{1}{2} \times 6.74 \times 4.35^2\)
Simplifying:
\(d = 0 + \frac{1}{2} \times 6.74 \times 18.9225\)
\(d = 60.657725\)
Therefore, after 4.35 seconds, the car has traveled approximately 60.66 meters.