A car is accelerating, from rest, at a rate of 6.74 m/s2. After 4.35 seconds, how far has the car gone?
To find the distance the car has gone, we can use the kinematic equation:
d = (1/2)at^2
where:
d is the distance,
a is the acceleration, and
t is the time.
Given:
a = 6.74 m/s^2,
t = 4.35 s.
Plugging in the values into the equation:
d = (1/2) * 6.74 * (4.35)^2
First, we square the time:
t^2 = 4.35^2 = 18.9225
Next, we can calculate the distance using the formula:
d = (1/2) * 6.74 * 18.9225
Simplifying the equation, we get:
d = 64.0226 m
Therefore, after 4.35 seconds, the car has gone approximately 64.02 meters.