What is the sum of all possible digits that could fill in the blank
in 47_021 so that the resulting five digit number is divisible by 3?
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im confused on how to go about the problem. that's y i need help on how to start.
4 + 7 + 2 + 1 = 14
What numbers can you put in the blank so that the numbers add up to 15, 18, and 21?
To find the sum of all possible digits that could fill in the blank in 47_021 so that the resulting five-digit number is divisible by 3, we need to determine the range of possible digits.
A number is divisible by 3 if the sum of its digits is divisible by 3. Therefore, to find the possible digits, we should add the missing digits that make the sum of all the digits in the number a multiple of 3.
Let's analyze the given number: 47_021.
For the number to be divisible by 3, the sum of its digits must be divisible by 3. The sum of the known digits in the number is 4 + 7 + 0 + 2 + 1 = 14.
To make this sum a multiple of 3, we need to add a digit that, when added to 14, will result in a multiple of 3.
We can start by finding the remainder when 14 is divided by 3, which is 2. This means that we need to add 1 to make the sum a multiple of 3.
Therefore, the only possible digit that could fill in the blank in 47_021 so that the resulting five-digit number is divisible by 3 is 1.
To find the sum of all possible digits, we only have one option, which is 1. So, the sum of all possible digits = 1.