What mass of Ca(OH) 2 is required to make 1.5 l of a 4.0% (w/v) solution of Ca(OH)2 in water?
percent(w/v)=mass/1500
mass=.04*1500 grams.
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To calculate the mass of Ca(OH)2 required, we need to use the formula:
Mass (g) = Volume (L) × Concentration (g/L)
First, let's convert the given volume from liters to milliliters (ml) since the concentration is usually expressed in grams per milliliter:
1.5 L = 1500 ml
Next, we need to calculate the concentration in grams per milliliter. The given concentration is 4.0% (w/v), which means 4.0g of Ca(OH)2 is present in 100 ml of solution:
Concentration (g/ml) = (4.0 g/100 ml)
Now, we can substitute the values into the formula:
Mass (g) = Volume (ml) × Concentration (g/ml)
Mass (g) = 1500 ml × (4.0 g/100 ml)
Simplifying the expression:
Mass (g) = 1500 ml × 0.04 g/ml
Mass (g) = 60 g
Therefore, 60 grams of Ca(OH)2 is required to make a 1.5 liter solution with a concentration of 4.0% (w/v).