a sample of an unknow metal exists as a perfect cube that meausres 0/78 in on a side and weighs 61.4 grams. what would be the mass, in grams, of a diff sample of this metal that has a volume of 25.0 cm^3
Did you make a typo on 0/78 inches?
yes. i meant 0.78 sorry.
Convert 0.78 inches to ?cm. Then
volume of the cube = (?cm)^3.
density = mass/volume. You have mass and volume, solve for density.
Then mass = volume x density.
volume 25.0 cc.
density from above.
To determine the mass of a different sample of the metal with a volume of 25.0 cm³, we need to use the density of the metal.
Density is defined as mass divided by volume (Density = Mass / Volume).
To find the density, we need to first calculate the mass of the original sample.
Given that the original sample is a perfect cube with each side measuring 0.78 inches, we can calculate the volume using the formula:
Volume = length * width * height
Since all sides are equal for a cube, the volume of the original sample is:
Volume = 0.78 inches * 0.78 inches * 0.78 inches
Now, let's convert the volume to cm³, as we want to use centimeters for consistency:
1 inch = 2.54 cm
Converting the original volume:
Volume = (0.78 inches * 2.54 cm/inch) * (0.78 inches * 2.54 cm/inch) * (0.78 inches * 2.54 cm/inch)
Volume ≈ 0.78 cm * 0.78 cm * 0.78 cm
Now, let's calculate the mass of the original sample:
Mass of the original sample = 61.4 grams
Now, we can find the density of the metal:
Density = Mass / Volume
Density = 61.4 grams / (0.78 cm * 0.78 cm * 0.78 cm)
Now, we can use the density to determine the mass of the different sample with a volume of 25.0 cm³:
Mass = Density * Volume
Mass = (Density of the metal) * (25.0 cm³)