If your body develops a charge of -18 (microcoulombs), how many excess electrons has it acquired?
One electron has a charge of 1.6E-19 coulombs
16E-19 coulombs/e x #e = 18E-6 coulombs.
Solve for #e.
If your body develops a charge of -10 (microcoulombs), how many excess electrons has it acquired?
and what is their collective mass
To determine the number of excess electrons your body has acquired when it develops a charge of -18 microcoulombs, we need to use the concept of elementary charge and the formula Q = ne, where Q represents the charge, n represents the number of excess electrons, and e represents the elementary charge.
The elementary charge (e) is the charge carried by a single electron, which is approximately equal to 1.6 x 10^-19 coulombs.
First, we need to convert the charge of -18 microcoulombs to coulombs. Since 1 microcoulomb is equal to 10^-6 coulombs, we can convert -18 microcoulombs to coulombs as follows:
-18 microcoulombs x (10^-6 coulombs/1 microcoulomb) = -1.8 x 10^-5 coulombs
Now, we can use the formula Q = ne to find the number of excess electrons (n). Rearranging the formula, we have:
n = Q/e
Substituting the values, we have:
n = (-1.8 x 10^-5 coulombs) / (1.6 x 10^-19 coulombs/electron)
n ≈ -1.13 x 10^14 electrons
Therefore, when your body develops a charge of -18 microcoulombs, it has acquired approximately -1.13 x 10^14 excess electrons.