A rock is thrown upward at 65.2
◦
with respect
to the horizontal. As it rises, its vertical
component of velocity
... decreases to zero. Then it comes back down
To find the vertical component of velocity of the rock as it rises, we'll need to break down the given information and use some basic physics principles.
First, let's clarify the given information: the rock is thrown upward at an angle of 65.2° with respect to the horizontal. This means that the rock doesn't move directly vertically; it has both a vertical and horizontal motion component.
The vertical component of velocity refers to the speed at which the rock is moving in the upward or downward direction. In this case, we're interested in the upward component of velocity as the rock rises.
To determine the vertical component of velocity, we'll need to use trigonometry. We can calculate it using the initial velocity and the angle of projection.
Let's assume the initial velocity of the rock is v₀ and its vertical component of velocity is v_vertical. The angle between the initial velocity and the vertical direction is 65.2°. Using trigonometry, we can write:
sin(65.2°) = v_vertical / v₀
Now, let's rearrange the equation to solve for v_vertical:
v_vertical = v₀ * sin(65.2°)
To find the vertical component of velocity, you'll need to know the initial velocity of the rock (v₀). If you have that information, plug it into the equation along with the value of the angle (65.2°) and calculate the result.