I'm not sure how to approach this problem. A manometer uses kerosene, specific gravity 0.82 as the fluid. A reading of 5 inches on the manometer is equivalent to how many millimeters of mercury?
Answer is 7.686mm.hg
pressure = density*g*height
5" = 5*25.4 mm = h in mm
p = 0.82 x 9.8 x 5 x 25.4 = ? Pa.
Divide by 1000 to convert to kPa.
Then ?kPa x (1 atm/101.325) x (760 mm/1 atm) = ? mm pressure.
Here is a good site for pressure of fluids.
http://hyperphysics.phy-astr.gsu.edu/hbase/pflu.html
zxsc
Ah, the wonderful world of converting units! Don't worry, I'm here to help you.
So, let's see. We need to convert 5 inches of kerosene to millimeters of mercury, right? Well, first, we'll have to turn the specific gravity of kerosene into something we can work with.
Now, the specific gravity of kerosene is 0.82. It's like saying kerosene is only 82% as cool as water. So, to convert that to millimeters of mercury, we'll multiply it by 13.6 because, well, why not?
Alright, now we're ready for some serious mathematics. So, we have 5 inches as the manometer reading, and we know that 1 inch is equal to around 25.4 millimeters. Don't worry, I won't ask you to remember that, because I know I can't remember it either!
Now, let's put it all together. We multiply 5 inches by 25.4 millimeters, and then we multiply that by 0.82 (our specific gravity of kerosene in millimeters of mercury). Are you still with me? Great!
After some quick calculations, you'll find that 5 inches of kerosene is equivalent to roughly 104.29 millimeters of mercury. Voila! Problem solved, and we all had a good laugh along the way.
To solve this problem, we need to convert the 5-inch reading on the manometer to millimeters of mercury.
First, let's understand the concept behind a manometer. A manometer measures the pressure difference between two points in a fluid-filled tube. In this case, the manometer uses kerosene as the fluid.
To convert the 5-inch reading on the manometer to millimeters of mercury, we need to calculate the pressure difference between the two points.
The pressure exerted by a column of liquid in a manometer is given by the equation:
P = ρgh
Where:
P = Pressure (in Pascals or N/m^2)
ρ = Density of the fluid (in kg/m^3)
g = Acceleration due to gravity (in m/s^2)
h = Height difference between the two points (in meters)
In this case, we are given the specific gravity of kerosene as 0.82. Specific gravity is the ratio of the density of a substance to the density of a reference substance. Therefore, we can calculate the density of kerosene (ρ_kerosene) using the specific gravity:
ρ_kerosene = ρ_reference * specific gravity
The density of water (ρ_reference) is approximately 1000 kg/m^3.
ρ_kerosene = 1000 kg/m^3 * 0.82
Next, we need to convert the 5-inch reading on the manometer to meters:
5 inches * 0.0254 meters/inch = 0.127 meters
Now, we have all the necessary values to calculate the pressure difference between the two points.
P = ρ_kerosene * g * h
P = (1000 kg/m^3 * 0.82) * 9.8 m/s^2 * 0.127 m
Calculating this gives us the pressure in Pascals.
To convert this pressure to millimeters of mercury, we use the conversion factor:
1 mmHg ≈ 133.322 Pascals
So, the final step is to convert the pressure in Pascals to millimeters of mercury:
Pressure (in mmHg) = P (in Pascals) / 133.322
Now you can calculate the pressure in millimeters of mercury by plugging in the values and performing the calculations.