Question

3n^4-4n^2=-1

Answer 1

3(n^2)^2 - 4(n^2) + 1 = 0

(3n^2-1)(n^2-1) = 0
(n√3-1)(n√3+1)(n-1)(n+1) = 0
n = ±1 or ±1/√3