A car traveling at 34.7 m/s and barkes with an acceleration of -3m/s^2 for 5 secons. How far does the car travel during the acceleration and what is the final velocity?
I really need help on these bad!
To determine how far the car travels during the acceleration, you can use the kinematic equation:
Δx = vi * t + (1/2) * a * t^2
where Δx is the displacement, vi is the initial velocity, a is the acceleration, and t is the time.
In this case, the initial velocity (vi) is 34.7 m/s, the acceleration (a) is -3 m/s^2 (negative because it's decelerating), and the time (t) is 5 seconds. Plugging these values into the equation, we get:
Δx = (34.7 m/s) * (5 s) + (1/2) * (-3 m/s^2) * (5 s)^2
Simplifying:
Δx = 173.5 m + (-37.5 m)
Δx = 136 m
Therefore, the car travels a distance of 136 meters during the acceleration.
To find the final velocity, you can use the equation:
vf = vi + a * t
where vf is the final velocity. Plugging in the values:
vf = 34.7 m/s + (-3 m/s^2) * (5 s)
Simplifying:
vf = 34.7 m/s + (-15 m/s)
vf = 19.7 m/s
Therefore, the final velocity of the car is 19.7 m/s.