two masses are in the ratio 1:2 are thrown vertically up with the same speed . what is the effect on time by the mass?
Mass doesnt influence time
s=ut+1/2*at^2
Distance travelled, initial velocity and acceleration of the two balls is same.
This means that both the balls take the same time(since s, u and a are equal).
So mass does not effect time.
When two masses are thrown vertically up with the same speed, the effect on time is that the lighter mass takes less time to reach the highest point compared to the heavier mass. This is due to the difference in their masses.
To understand why this happens, let's consider the physics behind it. According to the laws of motion, the time taken to reach the highest point for an object thrown vertically upwards depends on its initial velocity and the acceleration due to gravity.
The initial velocity is the same for both masses as they are thrown with the same speed. However, the acceleration due to gravity is constant for all objects near the surface of the Earth. It does not depend on the mass of the object.
Since the acceleration due to gravity is the same for both masses, but the lighter mass has less inertia, it can accelerate more quickly. As a result, it reaches the highest point faster compared to the heavier mass.
In summary, when two masses are thrown vertically up with the same speed, the lighter mass will take less time to reach the highest point compared to the heavier mass.
To determine the effect of the mass on the time taken for the masses to reach their maximum height, we can analyze the relation between mass and time in this scenario.
When an object is thrown vertically up, the only force acting on it is gravity, which opposes its motion. As a result, the object will experience deceleration as it moves upward. The time it takes for the object to reach its maximum height will depend on the magnitude of the gravitational force acting on it, which is determined by its mass.
According to Newton's second law of motion, the force acting on an object can be expressed as the product of its mass (m) and acceleration (a):
F = m * a
In this case, the force is the gravitational force (F = m * g), where g represents the acceleration due to gravity.
Since both masses are thrown vertically up with the same speed, we can assume their initial velocities (u) are the same. Additionally, the gravitational acceleration is a constant value near the Earth's surface, regardless of mass.
In this scenario, both masses experience the same gravitational force (F = m * g) and have the same initial velocity (u). Therefore, the gravitational force acting on them is the same, and they both experience the same deceleration. As a result, the time taken for both masses to reach their maximum height will also be the same.
Hence, the effect of mass on the time taken for the masses to reach their maximum height is negligible.