Which has the greater acceleration, a car that increases its speed from 50 to 62 km/h, or a bike that goes from 0 to 12 km/h in the same time?
a1 = (v-Vo)/t = (62-50)/t = 12/t.
a2 = (0-12) = -12/t.
Since their times and change in speed
are equal, the magnitude of their acceleration are equal. The neg. sign
means the bike was stopping or slowing
down.
The accelerations are the same.
To determine which vehicle has greater acceleration, we need to calculate the acceleration for each vehicle. Acceleration is defined as the change in velocity divided by the time taken for that change.
Let's start with the car:
Initial velocity (u) = 50 km/h
Final velocity (v) = 62 km/h
To calculate the acceleration of the car, we need to find the change in velocity (Δv) and the time taken (Δt) for that change. Since the initial velocity is 50 km/h and the final velocity is 62 km/h, the change in velocity (Δv) for the car is:
Δv = v - u
= 62 km/h - 50 km/h
= 12 km/h
Now, we need the time taken for the car to achieve this change in velocity. Unfortunately, you haven't provided the time it takes for the car to increase its speed from 50 km/h to 62 km/h. Please provide this information so we can calculate the car's acceleration accurately.
Moving on to the bike:
Initial velocity (u) = 0 km/h
Final velocity (v) = 12 km/h
Similar to the car, we need to find the change in velocity (Δv) and the time taken (Δt) for the bike. The change in velocity is:
Δv = v - u
= 12 km/h - 0 km/h
= 12 km/h
Again, we don't have the time taken for the bike to reach this change in velocity. Please provide this information as well so we can calculate the bike's acceleration accurately.
Once we have the time taken for both the car and the bike, we can compare their accelerations and determine which vehicle has greater acceleration.