A 980 kg car is pulling a 275 kg trailer. Together, the car and trailer have an acceleration of 2.12 m/s2 in the forward direction. Neglecting frictional forces on the trailer, determine the following (including sign).

Incomplete.

980+275=1225

To determine the following, we can use Newton's second law of motion, which states that the net force acting on an object is equal to the product of its mass and acceleration. In this case, we have a system consisting of a car and a trailer, so we need to consider the forces acting on both objects.

1. Determine the net force acting on the car:

The net force on the car can be found by multiplying its mass by its acceleration:
Net force on the car = mass of the car * acceleration
Net force on the car = 980 kg * 2.12 m/s²
Net force on the car = 2077.6 N (forward)

2. Determine the net force acting on the trailer:

Since the trailer is being pulled by the car, the net force on the trailer is the same as the net force on the car.
Net force on the trailer = 2077.6 N (forward)

3. Determine the force exerted by the car on the trailer:

The force exerted by the car on the trailer is equal to the net force on the trailer:
Force exerted by the car on the trailer = 2077.6 N (forward)

4. Determine the force exerted by the trailer on the car:

According to Newton's third law of motion, the force exerted by the trailer on the car is equal in magnitude but opposite in direction to the force exerted by the car on the trailer. Therefore, the force exerted by the trailer on the car is also 2077.6 N, but in the opposite direction (backward).

So, the answers are:
1. Net force on the car: 2077.6 N (forward)
2. Net force on the trailer: 2077.6 N (forward)
3. Force exerted by the car on the trailer: 2077.6 N (forward)
4. Force exerted by the trailer on the car: 2077.6 N (backward)