It takes 62 mL of 0.124 M KOH to neutralize
46.7 mL of H2SO4 solution. What is the
concentration of the H2SO4 solution?
Answer in units of moles/liter
the titration equation:
Normality of KOH*volumeKOH=Normalityacid*volume acid
1*molarityKOH*volumeKOH=2*Ma*volume acid
where Ma is the molaritiy of the acid.
solve for Molarity of the acid.
To find the concentration of the H2SO4 solution, you can use the concept of stoichiometry and the equation of the neutralization reaction. In this case, the neutralization reaction is as follows:
H2SO4 + 2KOH -> K2SO4 + 2H2O
From the balanced equation, we can see that 1 mole of H2SO4 reacts with 2 moles of KOH. Therefore, the moles of H2SO4 can be calculated by multiplying the volume of KOH used (in liters) by its concentration (in moles per liter) and dividing by 2:
moles of H2SO4 = (62 mL / 1000 mL/L) * (0.124 moles/L) / 2 = 0.003868 moles
Now we can find the concentration of the H2SO4 solution, which is the moles of H2SO4 divided by the volume of the solution (in liters):
concentration of H2SO4 = 0.003868 moles / (46.7 mL / 1000 mL/L) = 0.0828 moles/L
Therefore, the concentration of the H2SO4 solution is 0.0828 moles/L, which is the final answer.