A car starts from rest and accelerates uniformly over a time of 5.21 s for a distance of 110 m. Determine the acceleratin of the car
110=1/2a (5,21)(5,21) a=8,10
45+8548
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To determine the acceleration of the car, we can use the equation:
acceleration = (final velocity - initial velocity) / time
Given that the car starts from rest, its initial velocity (Vi) is 0 m/s.
We need to find the final velocity (Vf). To do this, we can use the equation:
Vf = Vi + acceleration * time
In this case, the final distance (d) is given as 110 m, so we can find the final velocity as follows:
Vf = sqrt(2 * acceleration * d)
Now, we can substitute the values into the equation and solve for the acceleration.
110 m = sqrt(2 * acceleration * 5.21 s)
Squaring both sides to remove the square root:
12100 m^2 = 2 * acceleration * 5.21 s
Simplifying:
acceleration = 12100 m^2 / (2 * 5.21 s)
acceleration ≈ 1169.1 m^2/s
Therefore, the acceleration of the car is approximately 1169.1 m^2/s.