science; AP Chem

I don't know how to find the kpa for 35.78 m in this question. I know its a P1V1=P2V2 question, i just need the kpa for 35.78m pls!

Divers know that the pressure exerted by
the water increases about 100 kPa with every
10.2 m of depth. This means that at 10.2 m
below the surface, the pressure is 201 kPa;
at 20.4 m below the surface, the pressure is
301 kPa; and so forth. If the volume of a
balloon is 3.9 L at STP and the temperature
of the water remains the same, what is the
volume 35.78 m below the water’s surface?
Answer in units of L

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asked by Anonymous
  1. when i tried to figure it out, i got 451 kpa but i don't think that's right..

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    posted by Anonymous
  2. If we use the 100 kPa/10.2 m your 451 is very close.
    100 x (35.78/10.2) = 452 kPa.
    If you figure it by physics
    density(g/cc) x depth(m) x gravity(m/s) = 1 g/cc x 35.78 x 9.8 = 350.6 and that plus the 1 atm on top is
    350.6 + 101.3 = 450.9.

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    posted by DrBob222
  3. ooh ok, thank you very much!
    this site is seriously a life saver!

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    posted by Fiona

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