If you put a 9th grade student in a bathtub and he foisted with most of his head and upper chest above water, how much water would spill out?

Additional Information:
Bathtub was full of the brim
Student is male, and has a normal male IQ (85)
Student weights 80kg
Student has a volume of 60000 cm3 ( cm cubed)
Student was face down, but who cares

Below, you will find a list of sentences. After each sentence, select true if the topic of the statement is suitable to form the basis of a single persuasive paragraph. If the topic of the statement in your textbook is unsuitable for a single persuasive paragraph, select false

To determine how much water would spill out of the bathtub when the 9th-grade student gets in, we need to calculate the volume of the student that is not submerged in the water and compare it to the volume of water already present.

First, let's calculate the volume of the student's body that is above the water level. The given volume of the student's body is 60000 cm3. However, since the student's head and upper chest are above water, not the entire volume is submerged. To estimate the submerged volume, we need to approximate the shape of the submerged portion.

Assuming the student's body shape is similar to a rectangular prism, we can calculate the volume of the submerged portion by multiplying the length, width, and height of the portion above water.

The average male body length from head to chest is approximately 60 cm. So, the length in this case would be 60 cm.

For the width, we can assume it to be the average shoulder width for a male, which is around 40 cm.

Since the depth of submersion is not provided, we cannot determine the exact height above the water level. However, let's assume it to be 20 cm as an estimate.

Now, we can calculate the volume of the submerged portion using the formula:
Volume = Length x Width x Height
Volume = 60 cm x 40 cm x 20 cm
Volume = 48000 cm3

Next, we need to calculate the volume of water already in the bathtub. Assuming the bathtub is full to the brim, we can estimate the average bathtub volume to be around 150 liters or 150,000 cm3.

Now, let's subtract the volume of the submerged portion (48000 cm3) from the volume of water in the bathtub (150,000 cm3) to find out how much water would spill out:
Spilled water volume = Volume of water - Volume of submerged portion
Spilled water volume = 150,000 cm3 - 48,000 cm3
Spilled water volume = 102,000 cm3

Therefore, approximately 102,000 cm3, or 102 liters, of water would spill out of the bathtub when the 9th-grade student is partially submerged with most of his head and upper chest above water.