The area of trapezium is 270cmsq. Nd its height is 6cm.if one of parallel sides is double the other,find the two parallel sides.
Ans is 30nd60cm
To find the lengths of the two parallel sides of the trapezium, let's use the formula for calculating the area of a trapezium:
Area = (1/2) * (sum of parallel sides) * height
We know that the area is 270 cm² and the height is 6 cm.
270 = (1/2) * (sum of parallel sides) * 6
Divide both sides of the equation by 6 to isolate the sum of parallel sides:
45 = (sum of parallel sides)
Let's assume one of the parallel sides is x cm. The other parallel side will be twice the length of x, so it would be 2x cm.
Now we can substitute these values into the equation:
45 = x + 2x
Combine like terms:
45 = 3x
Divide both sides of the equation by 3 to solve for x:
x = 15
Therefore, one of the parallel sides is 15 cm, and the other parallel side is 2 times 15:
First parallel side = 15 cm
Second parallel side = 2 * 15 = 30 cm
So, the two parallel sides of the trapezium are 30 cm and 15 cm.
To find the two parallel sides of a trapezium given its area and height, you can use the formula:
Area = ((sum of parallel sides) / 2) * height
Let's denote the two parallel sides as x and 2x (where 2x is double the other side). We can set up the equation as follows:
270 = ((x + 2x) / 2) * 6
First, simplify the equation:
270 = (3x / 2) * 6
Multiply both sides of the equation by 2/3 to isolate x:
(2/3) * 270 = 3x * 6
Multiply and simplify:
180 = 18x
Divide both sides of the equation by 18:
10 = x
So one parallel side measures 10 cm, and the other parallel side (which is double the first) measures 20 cm.
Therefore, the two parallel sides of the trapezium are 10 cm and 20 cm.
We know that, " Area of trapezium=1/2 * height * sum of parallel sides".
Let, one parallel side=x cm
Then the other parallel side=2x cm
So that,
Area=1/2 * 6 * (x+2x)=270
~ 9x=270
X=30
Hence,
Parallel sides are 30cm and 60cm.
B2 = 2B1.
A = 0.5(B!+2B!)6 = 270cm^2.
9B1 = 270
B1 = 30 cm.
B2 = 2*30 = 60 cm.