Factorize Xsquare-6x-3
x^2 - 6x - 3
does not factor over the rationals
i.e. We cannot find two rational number which when added give us -6 and when multiplied give us -3
If you want to "force" it , then
(x - 3+2√3)(x - 3 - 2√3)
does not factor over the rationals
i.e. We cannot find two rational number which when added give us -6 and when multiplied give us -3
If you want to "force" it , then
(x - 3+2√3)(x - 3 - 2√3)