This is the same equation as before just with different numbers.

y=yo + (vo sin Q) t - 1/2gt^2

This time the numbers are:

0 = 1.005 + (3.021 sin 30)t - 1/2(9.8)t^2

4.9t^2 - 1.5105 - 1.005 = 0
This is the part where I am stuck. Did I do this correctly? sin 30 = 0.50 X 3.021 = 1.5105 and then I would subtract this from 1.005

so then it would be 1.5105 - 1.005 = 0.5055 / 4.9 and square root it.

Math(Please check) - Reiny, Thursday, September 13, 2012 at 10:29am
You are making a similar mistake to yesterday's error.
Yesterday you just magically tagged a t at the end of the first term, now you are dropping the t from the second term

your equation of
0 = 1.005 + (3.021 sin 30)t - 1/2(9.8)t^2
looks ok, assuming your replacement values were correct
then
0 = 1.005 + 1.5105t - 4.9t^2 , since sin 30�‹ = 1/2

4.9t^2 - 1.5105t - 1.005 = 0 , look at yours

you will have to use the quadratic formula

t = (1.5105 �} �ã(1.5105^2 - 4(4.9)(-1.005) )/9.8
= .... you do the button-pushing

Math(Please check) - Steve, Thursday, September 13, 2012 at 10:33am
I think you dropped a t:

4.9t^2 - 1.5105t - 1.005 = 0

the coefficients are correct, so now you just have to solve the quadratic equation.

t = 0.154 �} �ã0.229

How did you get 0.154 and 0.229? When I try to complete the quadratic equation I am not getting these numbers.

To solve the quadratic equation, you can use the quadratic formula:

t = (-b ± √(b^2 - 4ac)) / (2a)

In this case, the equation is:

4.9t^2 - 1.5105t - 1.005 = 0

Comparing it with the general quadratic equation form ax^2 + bx + c = 0, we can see that a = 4.9, b = -1.5105, and c = -1.005.

Plugging in these values into the quadratic formula, we get:

t = (-(-1.5105) ± √((-1.5105)^2 - 4(4.9)(-1.005))) / (2(4.9))

Simplifying further:

t = (1.5105 ± √(2.28925 + 19.62)) / 9.8

t = (1.5105 ± √21.90925) / 9.8

Now, taking the square root of 21.90925:

t = (1.5105 ± 4.679) / 9.8

This gives us two possible solutions:

t = (1.5105 + 4.679) / 9.8 = 0.616

t = (1.5105 - 4.679) / 9.8 = -0.314

However, since time cannot be negative in this context, the only valid solution is t = 0.616.

Therefore, the correct answer is t = 0.616.