Calculus (Check)

This seems to easy. Check please.

Find.
Lim (x^2)-4
x->2 e

I substitute in 2
(2^2)-4
e

gives me
4-4
e

So my answer is e^0 or 1.

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  1. from the work that you show , I must assume you have

    Lim e^(x^2 - 4) as x-> 2

    = e^0 = 1

    you are correct

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