what is the answer to "construct a segment whose length is EF - CD and by the way a segment symbol is above the EF and CD
I will assume the usual sloppy use of quotation marks and interpret the question as
construct a segment whose length is EF - CD
Set the compass to the length of CD
Mark that distance on EF
The remainder of segment EF is EF-CD
To construct a segment whose length is EF - CD, you will need a ruler and a compass. Please follow these steps to construct the segment:
1. Draw a line segment EF, with the desired length. Label the endpoints as E and F.
2. Draw a line segment CD, also with the desired length. Label the endpoints as C and D.
3. Place the compass at point E and adjust the compass to the length of segment CD. This can be done by opening the compass to the length of CD, then keeping the same distance, place the compass tip on point E.
4. While keeping the compass open, draw an arc that intersects line segment EF. Label the point of intersection as G.
5. Now, place the compass at point G and adjust it to the length of segment EF.
6. While keeping the compass open, draw another arc that intersects line segment CD. Label the point of intersection as H.
7. Drawing a straight line between points H and F will give you the segment with a length of EF - CD.
Note: The segment symbol (a line with a double-headed arrow above it) can be added by indicating it, or by placing arrowheads on both ends of the constructed segment.
Remember to handle the compass carefully and maintain accurate measurements to ensure precise construction.