How do you determine the ymax? I know you have to use Q which I have values that were given to me as well as vo values but I am not sure what to do with these values.

To determine ymax, you need to use the equations of motion in physics. Specifically, you can use the following equation:

y = vo*t + (1/2)*a*t^2

In this equation, y represents the vertical displacement or height, vo is the initial vertical velocity, t is the time, and a is the acceleration (which is usually the acceleration due to gravity: approximately 9.8 m/s^2).

To find ymax, you need to find the point at which the vertical displacement stops increasing and starts decreasing, which corresponds to the highest point in the motion.

Here's how you can do it:

1. Start by setting the equation equal to zero, since at the highest point ymax, the vertical displacement y is zero:
0 = vo*t + (1/2)*a*t^2

2. Rearrange the equation to solve for t:
(1/2)*a*t^2 + vo*t = 0

3. Notice that this is a quadratic equation in terms of t. You can solve it by factoring if possible, or by using the quadratic formula:
t = (-vo ± √(vo^2 - 4*(1/2)*a*0)) / (2*(1/2)*a)

Simplifying the equation further gives:
t = (-vo ± √(vo^2)) / a

Since the plus/minus sign will not affect the value of t, you can write the formula as:
t = (-vo) / a

4. After finding the value of t, substitute it back into the original equation to find ymax:
ymax = vo*t + (1/2)*a*t^2

By plugging in the values of vo (initial vertical velocity) and a (acceleration due to gravity), you can calculate the value of ymax, which represents the maximum height reached in the motion.