algerbra 2

the perimeter of the rectangular playing field is 462 yards. The length of the field is 5 yards less than the triple width. What are the dimensions of the playing field.

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  1. P = 2L + 2W

    462 = 2(3W - 5) + 2W

    462 = 6W - 10 + 2W

    462 = 8W - 10

    462 + 10 = 8W

    472 = 8W

    59 = W

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    Ms. Sue

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