Question

i need help on these three..thank you...find the real number solutions of the equation..-2v^6=16

2h^5-12=-16h
3q^4+3q^3=6q^2+6q

Answer 1

-2v^6=16

Are you sure about the - sign?
Any real number to the sixth power is positive, and multiplying it by -2 would require -2v^6 to be negative. The left side could never equal 16.