Calc
 👍
 👎
 👁

 👍
 👎
Respond to this Question
Similar Questions

Calculus
For the function f whose graph is given, state the following (a) lim x → ∞ f(x) (b) lim x → −∞ f(x) (c) lim x → 1 f(x) (d) lim x → 3 f(x) (e) the equations of the asymptotes (Enter your answers as a commaseparated

Calculus Limits
Question: If lim(f(x)/x)=5 as x approaches 0, then lim(x^2(f(1/x^2))) as x approaches infinity is equal to (a) 5 (b) 5 (c) infinity (d) 1/5 (e) none of these The answer key says (a) 5. So this is what I know: Since

Calculus
Let f be a function defined for all real numbers. Which of the following statements must be true about f? Which might be true? Which must be false? Justify your answers. (a) lim of f(x) as x approaches a = f(a) (b) If the lim of

Calculus
Find the limit. lim 5x/(x^225) x>5 Here is the work I have so far: lim 5x/(x^225) = lim 5x/(x5)(x+5) x>5 x>5 lim (1/x+5) = lim 1/10 x>5 x>5 I just wanted to double check with someone and see if the answer is

Precal
Please determine the following limits if they exist. If the limit does not exist put DNE. lim 2+6x3x^2 / (2x+1)^2 x>  infinity lim 4n3 / 3n^2+2 n> infinity I did lim 2+6x3x^2 / (2x+1)^2 x>  infinity (2+6x3x²)/(4x²+4x+1)

Calculus Answer Confirming Not Sure Im Right Help?
Evaluate the lim a. lim x> 64 (cube root x4/x64) (∛x4)/(x64) > 0/0 so then let cube root x = u u4/u^364 u4/u^364 = u4/u4(u^2+4u+16) the u4 cancel each other out leaving lim x>64 = 1/u^2+4u+16 1/64^2+4(64)=16 oddly

calc bc (condensed
is the limit as x approaches 0 of sin3x over 3x equal to zero? sorry basically this is my problem: lim [sin 3x / 4x) x> 0 ~~~~I multiplied& eventually got to .75* lim (sin 3x / 3x) x> 0 ~so i figured since (lim (sinx/x) x> 0

Calculus
How do I solve lim(x>pi/4)(sinxcosx)/cos(2x) The (x>pi/4) goes below the lim. Should i just substitute the x's with pi/4??

calc
need to find: lim as x > 0 of 4(e^2x  1) / (e^x 1) Try splitting the limit for the numerator and denominator lim lim x>0 4(e^2x1) (4)x>0 (e^2x1) ______________ = ________________ lim lim x>0 e^X1 x>0 e^x1 Next solve for

Calculus
Find the indicated limits. If the limit does not exist, so state, or use the symbol + ∞ or  ∞. f(x) = { 2  x if x ≤ 3 { 1 + 3x  x^2 if x > 3 a) lim 3+ f(x) x>3 b) lim 3 f(x) x>3 c) lim f(x) x>3 d) lim ∞ f(x) x>3

PreCalculus
Which of the following shows the correct notation for “The limit of x^2  1 as x approaches 3. A. lim x^21 x>3 B. lim3 x>x^21 C. lim(x^23) x>x^21 D. lim(x^21) x>3 Thank you

Check my CALCULUS work, please! :)
Question 1. lim h>0(sqrt 49+h7)/h = 14 1/14*** 0 7 1/7 Question 2. lim x>infinity(12+x3x^2)/(x^24)= 3*** 2 0 2 3 Question 3. lim x>infinity (5x^3+x^7)/(e^x)= infinity*** 0 1 3 Question 4. Given that: x 6.8 6.9 6.99 7.01
You can view more similar questions or ask a new question.