Classify the following as ether, ketone, ester, amide, etc.
1) CH3CH2CNH2
!!
O
The !! represents a double bond and it is below the CN
I think this is an amide.
2) CH3COCH3
!!
O
The doube bond is below the CO
I think this is an ester.
3) CH3CCH3
!!
O
The double bond is below the CC
I think this is a ketone.
Would you agree with my answers?
You are right for all three. Good work.
Thank you very much!!
I agree with your answers for questions 1 and 2, but question 3 needs a bit of clarification. Let's go through each compound one by one:
1) CH3CH2CNH2:
This compound has an amino group (-NH2) attached to a carbon atom, which is named as an amine. The presence of the carbonyl group (C=O) right next to the nitrogen atom indicates that this compound is an amide. Therefore, your classification of amide is correct.
2) CH3COCH3:
This compound has a carbonyl group (C=O) located between two carbon atoms. When the carbonyl group is flanked by two alkyl (or aryl) groups, it is called a ketone. Your classification of ester for this compound is incorrect.
3) CH3CCH3:
This compound has a double bond (represented by "!!") located between two carbon atoms. There is no carbonyl group present. A compound with a double bond directly connected to a carbon atom on both sides is called an alkene, not a ketone.
Therefore, to properly classify compound 3, you would label it as an alkene.
So, to summarize:
1) CH3CH2CNH2 = Amide
2) CH3COCH3 = Ketone (not an ester)
3) CH3CCH3 = Alkene (not a ketone)
I hope this explanation helps!