Calculate the volume of water, in milliliters, that would be displaced by a piece of gold weighing 18.2g.
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To calculate the volume of water displaced by a piece of gold, we need to use the concept of density. Density is defined as mass per unit volume, and it provides a measure of how much matter is packed into a given space.
First, let's gather the necessary information:
1. The mass of gold: 18.2 grams (g).
2. The density of gold: 19.3 grams per cubic centimeter (g/cm³).
3. The density of water: 1 gram per milliliter (g/mL) or 1 gram per cubic centimeter (g/cm³).
Now, we can proceed with the calculation using the formula:
Volume = Mass / Density
Step 1: Convert the mass of gold to grams.
The mass of gold is already given in grams, so no conversion is needed.
Step 2: Calculate the volume of gold.
Volume of gold = Mass of gold / Density of gold
Volume of gold = 18.2 g / 19.3 g/cm³
Step 3: Convert the volume of gold to milliliters.
The density of water is given in grams per milliliter, which means 1 milliliter of water weighs 1 gram or has a density of 1 g/mL.
Volume of water = Volume of gold in cm³ * 1 mL/cm³
Now, let's substitute the values into the equation:
Volume of water = (18.2 g / 19.3 g/cm³) * 1 mL/cm³
Calculating this expression will give you the volume of water displaced by the piece of gold in milliliters.