When drawing a kekule structure for

CH3CH2OH(alcohol) do I leave the OH at the end just like it is (OH) or would it be shown as O-H?

I know that to start of it would be

-C- with an H on the top and the bottom as well as the left side and then connected to the C would be another C with H above and below. Im just not sure how to show the OH part. Thank you.

C-C-C-O-H

Ok thank you so for something like an amine with an NH2 would I show it the same way N with an H above and below??

yes

H-N-R
...|
...H

It's hard to make spaces on this board. I try periods to make the spacing come out right Sometimes that works and sometimes it doesn't.

Do you have to show the R?

I need to show the kekule structure for
CH3CONH2. I know how to start it off Im just not sure about the NH2. The N would be connected to a carbon on the left side correct?

N must have three bonds so I used R for the third bond. It stands for anything you wish; i.e., it could be a CH3 group, and ethyl group (CH3CH2-)or whatever you wish.

When drawing a Kekule structure for CH3CH2OH (ethanol), you can represent the hydroxyl group (OH) in two different ways:

1. Leave it as (OH): In this representation, you draw the oxygen (O) as a connecting atom, and the hydrogen (H) as a separate atom attached to it. So, your structure would look like this:

H H
| |
H-C-C-C-H
| |
H (OH)

2. Show it as O-H: In this representation, you combine the oxygen (O) and hydrogen (H) atoms into one group, collectively referred to as "O-H." So, your structure would look like this:

H H
| |
H-C-C-C-OH
| |
H

Both representations are correct and valid. The choice depends on personal preference or the specifications given to you.

Remember, while drawing Kekule structures, it is essential to show the correct connectivity of atoms and the arrangement of bonds. Pay attention to the correct number of hydrogen atoms connected to each carbon atom.