Find the area of a rectangular plot whoselength is 48m and a diagonal is 50m. Gve me soltn fst nd ans 672m^2?
48^2 + b^2 = 50^2
2304 + b^2 = 2500
b^2 = 196^2
b = 14
To find the area, multiply 14 * 48
Thank u :)
To find the area of a rectangular plot, we need to know either the length and width or the length and diagonal of the rectangle. In this case, we know the length is 48m and the diagonal is 50m.
To find the width of the rectangle, we can use the Pythagorean theorem, which states that in a right triangle, the square of the hypotenuse (the longest side) is equal to the sum of the squares of the other two sides.
In this case, the length is one side of the right triangle, the width is the other side, and the diagonal is the hypotenuse. We can set up an equation using the Pythagorean theorem:
(width)^2 + (length)^2 = (diagonal)^2
Let's substitute the given values:
(width)^2 + (48m)^2 = (50m)^2
Simplifying the equation:
(width)^2 + 2304m^2 = 2500m^2
Subtracting 2304m^2 from both sides:
(width)^2 = 196m^2
Taking the square root of both sides:
width = √196m^2
width = 14m
Now that we have the width and length of the rectangle, we can find the area by multiplying these two values:
Area = length x width
= 48m x 14m
= 672m^2
So, the area of the rectangular plot is 672m^2.