what is the equation of the given line in standard form. use integer coefficients
y=-1.7x+8.5
Please explain not understanding
Y = -1.7x + 8.5.
1. Gather all variables to the left side
of the Eq and gather the constant to the rt. side.
1.7x+ Y = 8.5.
2. Multiply both sides by 10 to eliminate all decimals.
17x + 10y = 85.
What is the equation of the given line in standard form? Use integer coefficients.
y = -6.9x + 5.1
A. 69x + 10y = 51
B. -69x + 10y = 51
C. -69x + 10y = -51
D. 69x + 10y = -51
To convert the equation of the given line, y = -1.7x + 8.5, to standard form with integer coefficients, we need to eliminate the decimal coefficients and have only integers.
In this case, we can begin by multiplying every term in the equation by 10 so that the decimal coefficients become whole numbers:
10y = -17x + 85
Next, we need to rearrange the equation so that it follows the standard form, which is Ax + By = C, where A, B, and C are integers.
To make the x term positive, we multiply everything by -1:
-10y = 17x - 85
Now, we bring the x and y terms to the left-hand side of the equation:
17x + 10y = 85
So, the equation of the given line in standard form with integer coefficients is 17x + 10y = 85.
To convert the equation of a line from slope-intercept form (y = mx + b) to standard form (Ax + By = C) with integer coefficients, follow these steps:
1. Multiply both sides of the equation by 10 (or any number that eliminates the decimal):
10y = -17x + 85
2. Rearrange the equation to isolate the variables on one side:
17x + 10y = 85
3. If necessary, multiply the entire equation by -1 to make the coefficient of x positive:
-17x - 10y = -85
Therefore, the equation of the given line in standard form with integer coefficients is -17x - 10y = -85.