I just want to check if I am correct on this Q:

What is the major product formed when 1-butene reacts with water in the presence of dilute sulphuric acid?

a) 1-butanol
b) 2-butanol
c) butane
d) 1-methylpropanol

I "think" that it "should" be "B" (2-butanol)???

ignore this post.

To determine the major product formed when 1-butene reacts with water in the presence of dilute sulfuric acid, we need to consider the mechanism of the reaction.

The reaction you described is an acid-catalyzed hydration of an alkene, known as an addition reaction. In this case, water reacts with 1-butene to form an alcohol.

The reaction mechanism proceeds in two steps:

1. Protonation: The alkene (1-butene) reacts with an acid (sulfuric acid) to form a carbocation. The sulfuric acid donates a proton, which attaches to one of the carbon atoms in the double bond, creating a positive charge on that carbon atom.

2. Nucleophilic attack: Water (H2O) serves as a nucleophile and attacks the positively charged carbon atom. The water molecule donates a lone pair of electrons to form a bond with the carbon atom, resulting in the formation of an alcohol.

Since the reaction occurs at the more substituted carbon atom, the major product will be the alcohol derived from the more substituted carbon atom.

Let's analyze the options:

a) 1-butanol: This corresponds to the alcohol derived from the less substituted carbon atom. It is not the major product.

b) 2-butanol: This corresponds to the alcohol derived from the more substituted carbon atom. This is the major product.

c) butane: This is not formed in the reaction described.

d) 1-methylpropanol: This is not formed in the reaction described.

Therefore, your choice of option B (2-butanol) is correct.