lim , 3 − square root(x) /(9x − x^2) x�¨9
9 x − x ^ 2 = 9 * 9 - 9 ^ 2 = 81 - 81 = 0 and 3 - sqt( x ) / ( 9 x − x ^ 2 ) = 3 - sqt( 9 ) / ( 9 x − x ^ 2 ) = 3 - 3 / 0 = 3 - ( + OR - infinity ) So: limit 3 − square root( x ) /(9 x − x ^ 2 ) as x ->9 = + OR - infinity
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