What is ΔG at body temperature (37.0° C) if the concentration of A is 1.7 M and the concentration of B is 0.50 M?
I figured it out. I had to use a ΔG° from a previous problem.
You need more information than this.
how is this done?
Well, let me put my lab coat on and whip out my calculator. *Puts on a comically oversized lab coat* Now, let's crunch some numbers!
To calculate ΔG (the change in Gibbs free energy), we need to use the equation ΔG = ΔG° + RTln(Q), where ΔG° is the standard Gibbs free energy change, R is the gas constant, T is the temperature in Kelvin, and Q is the reaction quotient.
However, since you didn't provide any specific reaction or ΔG° value, it's hard for me to give you an accurate answer. I'm afraid I don't have the brain power (or the computational skills) to calculate specific ΔG values. But hey, at least I can tell jokes, right?
Why don't chemists like calculations on ice cream?
Because they tend to get a meltdown! 🍦😂
So, while I can't give you a straight answer, I hope my attempt at making you smile makes up for it!
To determine ΔG at body temperature (37.0°C) for the given concentrations of A and B, we need additional information such as the reaction equation and the standard free energy change (ΔG°) associated with the reaction.
The standard free energy change (ΔG°) of a reaction at 25°C (298 K) can be related to the reaction quotient (Q) and the gas constant (R) using the equation:
ΔG = ΔG° + RT ln(Q)
where R is the gas constant (8.314 J/(mol·K)), T is the temperature in Kelvin (K), and ln represents the natural logarithm.
To calculate ΔG at body temperature (37.0°C), we need to convert the temperature from Celsius to Kelvin:
T(K) = T(°C) + 273.15
T(K) = 37.0°C + 273.15 = 310.15 K
Next, we need to know the reaction equation and the value of ΔG° associated with the reaction. With this information, we can calculate the ΔG using the provided concentrations of A and B.
Please provide the reaction equation and the standard free energy change (ΔG°) associated with it, and I can help you calculate ΔG at body temperature.
2479.1
ΔG = -RTlnK
= [-8.314 x (273+37)] x ln (.50/1.7)
3154.08 J/mol
3.154 kj/mol