okay Math genius! Help me out here. I am a number greater than 99 and less than 1,000. Two of my digits that aren't next to each other are the same. My tens digit could not be greater and it is 1 more than my hundreds digit. What number am I?
since 10's is the max digit, which is 9,
tens=9
hundreds=8
It's a 3-digit number, or it would be over 1000.
So, the number is 89x
but two digits not adjacent are the same, so that would make the number
898
iam the largest 4 digit number with 4 different digits who am i?
To find the number, let's follow the given clues step by step:
1. The number is greater than 99 and less than 1,000. This means the number is a three-digit number.
2. Two of the digits that aren't next to each other are the same. This tells us that one of the digits appears twice in the number but is not in a consecutive position.
3. The tens digit could not be greater, and it is 1 more than the hundreds digit. This means the tens digit is greater than the hundreds digit but only by one.
Using these clues, we can deduce the following:
Since the number is greater than 99, its hundreds digit can only be 1 or 2. Let's examine both possibilities:
1. If the hundreds digit is 1, then the tens digit would be 2 (since it is greater by one). This would mean the units digit cannot be 2 or 1 (to fulfill the condition of non-consecutive repeated digits). However, this would not satisfy the condition of being less than 1,000. So, this case can be ruled out.
2. If the hundreds digit is 2, then the tens digit would be 3 (since it is greater by one). Now, we need to find a suitable digit for the units digit that is not 3 (to fulfill the condition of non-consecutive repeated digits). There are a few options: 0, 1, 4, 5, 6, 7, 8, or 9.
Since the problem does not specify any further restrictions, we can choose any digit from the list provided. Therefore, the number that satisfies all the given conditions is 231.
So, the number you are is 231.