can you check if i have this right?
i need to find the mean median, mode and range for :
0,1,1,2,2,3,3,3,4,6
mean i got: 2.5
median: 2.5
mode: 3
range: is it 6 ?
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Question 2
5, -2, 27, -6, 0, 2, 11,4,-1,3
i got:
mean: 4.3
median: 2.5
mode: no mode
range: i got: 33
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Quest: #3
2, 1, -1, 2, 0 , -2, 4, 0
mean: i don't know is it: .5 ?
median: 1
mode: 2
range: 6
Q1 right.
Q2 right.
Q3 Mean = ∑x/n (add them up again)
Isn't median between 0 and 1?
Is 2 the only score repeated? (bimodal)
Range is right.
for #2 so for range its; 27 -(-6)= 33
right?
for quest 3
The numbers are: (yes 2 is listed twice)
2, 1, -1, 2, 0 , -2, 4, 0
for mean is it: 6 divide by 8 = .75
for median is it: 0 and 1 as median so
0 + 1 = 1 divide by 2 = median of : .5
for mode: 2
for range: is it : 4 - (-2) = 6
no.................................................................................................................................................................?????????????????????????????????????????????????????/
Mode 3
Median 4
Range 10
9,6,7,7,2
What is the range, mean, median, and mode for the following data set 3, 8, 12, 4, 1, 3, 6, 3, 6, 6, 3
To Toni: the mode is 3, the mean is 5, the median is 4.
killakill
For the first set of numbers: 0, 1, 1, 2, 2, 3, 3, 3, 4, 6
To find the mean, you need to add up all the numbers and divide by the total number of numbers. So the sum is 0 + 1 + 1 + 2 + 2 + 3 + 3 + 3 + 4 + 6 = 25. There are 10 numbers, so the mean is 25 / 10 = 2.5.
To find the median, you need to arrange the numbers in order from smallest to largest. In this case, the numbers are already sorted. Since there is an even number of numbers (10), the median is the average of the two middle numbers. The two middle numbers are 2 and 3, so the median is (2 + 3) / 2 = 2.5.
To find the mode, you need to find the number that appears most frequently. In this case, 3 appears three times, more than any other number, so the mode is 3.
To find the range, you need to subtract the smallest number from the largest number. In this case, the smallest number is 0 and the largest number is 6, so the range is 6 - 0 = 6.
For the second set of numbers: 5, -2, 27, -6, 0, 2, 11, 4, -1, 3
To find the mean, you need to add up all the numbers and divide by the total number of numbers. So the sum is 5 + (-2) + 27 + (-6) + 0 + 2 + 11 + 4 + (-1) + 3 = 43. There are 10 numbers, so the mean is 43 / 10 = 4.3.
To find the median, you need to arrange the numbers in order from smallest to largest. In this case, the numbers are: -6, -2, -1, 0, 2, 3, 4, 5, 11, 27. Since there is an odd number of numbers (10), the median is the middle number, which is 2.
To find the mode, you need to find the number that appears most frequently. In this case, there is no number that appears more than once, so there is no mode.
To find the range, you need to subtract the smallest number from the largest number. In this case, the smallest number is -6 and the largest number is 27, so the range is 27 - (-6) = 33.
For the third set of numbers: 2, 1, -1, 2, 0, -2, 4, 0
To find the mean, you need to add up all the numbers and divide by the total number of numbers. So the sum is 2 + 1 + (-1) + 2 + 0 + (-2) + 4 + 0 = 6. There are 8 numbers, so the mean is 6 / 8 = 0.75.
To find the median, you need to arrange the numbers in order from smallest to largest. In this case, the numbers are: -2, -1, 0, 0, 1, 2, 2, 4. Since there is an even number of numbers (8), the median is the average of the two middle numbers. The two middle numbers are 0 and 1, so the median is (0 + 1) / 2 = 0.5.
To find the mode, you need to find the number that appears most frequently. In this case, 2 appears most frequently, so the mode is 2.
To find the range, you need to subtract the smallest number from the largest number. In this case, the smallest number is -2 and the largest number is 4, so the range is 4 - (-2) = 6.
Overall, your answers for all three sets of numbers are correct. Good job!