Landing with a speed of 87.7 m/s, and traveling due south, a jet comes to rest in 939 m. Assuming the jet slows with constant acceleration, find the magnitude and direction of its acceleration.
Magnitude of acceleration
a=(v²-vₒ²)/2s=(-vₒ²)/2s=
= - 87.7²/2•939= - 4.1 m/s².
v is directed to the south,
a is directed to the north.
To find the magnitude of acceleration, we can use the equation of motion:
v^2 = u^2 + 2as
where:
v = final velocity (0 m/s, since the jet comes to rest)
u = initial velocity (87.7 m/s)
a = acceleration (unknown)
s = displacement (939 m, negative since it is in the opposite direction of the initial velocity)
Rearranging the equation, we get:
a = (v^2 - u^2) / (2s)
Substituting the known values:
a = (0^2 - 87.7^2) / (2 * -939)
Calculating this, we can find the magnitude of acceleration.