If JK=9x+11 and NO=28, what is the value of x
To find the value of x, we need to use the given equation JK = 9x + 11 and the additional information that NO = 28.
To solve for x, we need to isolate x on one side of the equation. Let's rearrange the equation to do that:
JK = 9x + 11
Subtract 11 from both sides:
JK - 11 = 9x
Now, we can divide both sides by 9 to solve for x:
(JK - 11)/9 = x
Since the value of NO is given as 28, we can substitute it into the equation:
((JK - 11)/9) = x
Now, we can substitute JK with NO:
((28 - 11)/9) = x
Simplifying the equation:
(17/9) = x
Therefore, the value of x is 17/9.