physics

Hello everyone, I need help with this question:

A dart gun is fired while being held horizontally at a height of 1.00m above ground level and while it is at rest relative to the ground. The dart from the gun travels a horizontal distance of 5.00m. A college student holds the same gun in a horizontal position while sliding down a 45.0 degree incline at a constant speed of 2.00m/s. How far will the dart travel if the student fires the gun while it is 1.00m above the ground?

Thanks very much!

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  1. As far as it wants! Your most welcome! :-)

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  2. (a)
    h=gt²/2 =>
    t =sqrt(2h/g)=
    =sqrt(2•1/9.8) =0.45 s
    s=v(x) •t =>
    The dart initial speed is
    v(x) = s/t =5/0.45=11.07 m/s.
    (b) v(y) =v•sin45º=2•0.707 =1.41m/s
    h=v(y) •t +gt²/2
    gt²/2 + v(y) •t –h =0,
    4.9 t² +1.41•t -1 =0
    t1=0.33 s. t2 - negative root
    s1=v(x) •t1= 11.07•0.33=3.66 m.

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  3. Elena's answer is wrong
    last step should be 12.48(0.33)
    answer is 4.12m

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  4. the time is supposed to be given , it was 0.329

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