# math

find the x intercepts of a parabola whenthe vertex is at 2,13 and y intercept at 0,5

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1. the generic equations of parabola is:

y=ax^2+bx+c

by information of the vertex 2;13 i have two facts:
i) 13=a*2^2+b*2+c ....replacing(2;13)
ii)the director of the vertex as equation:
x=-b/2a

by information "intercept at 0,5 ":
iii)5=a*0^2+b*0+c ....replacing(0;5)

tre equation tre unknowns a,b,c
you solve the system

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2. i forgot to specify in ii) x=-b/(2a) => 2=-b/(2a)

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