math

find the x intercepts of a parabola whenthe vertex is at 2,13 and y intercept at 0,5

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  1. the generic equations of parabola is:

    y=ax^2+bx+c

    by information of the vertex 2;13 i have two facts:
    i) 13=a*2^2+b*2+c ....replacing(2;13)
    ii)the director of the vertex as equation:
    x=-b/2a

    by information "intercept at 0,5 ":
    iii)5=a*0^2+b*0+c ....replacing(0;5)

    tre equation tre unknowns a,b,c
    you solve the system

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  2. i forgot to specify in ii) x=-b/(2a) => 2=-b/(2a)

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