Physics

A balloonist, riding in the basket of a hot air balloon that is rising vertically with a constant velocity of 9.5 m/s, releases a sandbag when the balloon is 44.3 m above the ground. Neglecting air resistance, what is the bag's speed when it hits the ground? Assume g = 9.80 m/s2.

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asked by Sherry
  1. Set up the formula,

    4.9t^2 +9.5 -44.3 use the quadratic formula to get 2.19 for t.

    44.3 = 1/2(9.5 +Vf)2.19

    = 30.96 m/s

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    posted by Demont

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