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A cannon on a level plain is aimed 50 degrees above th e horizontal and a shell is fired with a muzzle velocity of 1200 ft/s toward a vertical cliff 3200 ft away. How far above the bottom does the shell strike the side wall of the cliff?

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  1. First, calculate the time t required to reach the wall.
    3200 = 1200 cos50 * t

    Then use that t and the equation below for the height Y.

    Y = 1200sin50*t - (g/2)*t^2
    Where g = 32.2 ft/s^2

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