math

according to the smithsonian institute, many of the original stones were removed and or eroded. The length of one side of the square base originally measured 207 ft. less than twice the height. The original volume of the great pyramid was 91,394,008 ft.cubed. Use the formula for the volume of a square pyramid to calculate the original base and original height of the great pyramid...
the formula is Vsquare pyramid=1/3L^2H

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asked by angie
  1. L = 2h - 207
    so
    L^2 = (4 h^2 - 828 h + 42849)

    (1/3) L^2 h = 91,394,008
    (1/3)(4 h^3 - 828 h^2 + 42,849 h )= 91,394,008

    4 h^3 - 828 h^2 + 42,849 h - 274,182,024 =0
    try h = 450
    364,500,000 - 167,670,000 + 19,282,050-274,182,024 =-58,069,974
    try h = 475
    428,687,500 - 186,817,500 + 20,353,275 -274,182,024 = -11,958,749
    try h = 480
    442,368,000 - 190,771,200 + 20,567,520 - 274,182,024 = -2,017,704
    graph these and look for where it hits zero, probably around 481 ft

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    posted by Damon

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