ajay gets 20 percent less marks than that of vatsals marks. by what percentsvatsals marks is more than Ajays marks
since a = .8v,
v = 1.25a, or 25% greater
To find the percentage by which Vatsal's marks are more than Ajay's marks, we can follow these steps:
Step 1: Let's assume Vatsal's marks as "x".
Step 2: Ajay's marks are 20% less than Vatsal's marks. This means Ajay's marks would be 80% (100% - 20%) of Vatsal's marks.
Step 3: Convert 80% into decimal form by dividing it by 100: 80% = 0.8.
Step 4: To find the percentage difference, subtract Ajay's marks from Vatsal's marks and divide it by Ajay's marks: (x - 0.8x) / 0.8x.
Step 5: Simplify the expression using basic algebra: (0.2x) / 0.8x = 0.2 / 0.8 = 0.25.
Step 6: Multiply the result by 100 to convert it into a percentage: 0.25 * 100 = 25%.
Therefore, Vatsal's marks are 25% more than Ajay's marks.