1.A book and a bookmark together sell for $10.10. If the price of the book is $10 more than the price of the bookmark ,find the price of the book and the price of the bookmark.
bookmark- x book- x+10
equation: 10.10=x+(x+10))
solve for x. then plug in your answer to get the price of the book and the bookmark.
.10
X=10
To solve this problem, let's use algebraic equations.
Let's assume the price of the bookmark is x dollars. According to the given information, the price of the book is $10 more than the price of the bookmark, which means the price of the book is x + $10.
We are also given that the book and bookmark together sell for $10.10. So, we can set up the equation:
x + (x + $10) = $10.10
Now, let's solve for x:
2x + $10 = $10.10
Subtract $10 from both sides:
2x = $10.10 - $10
2x = $0.10
Divide both sides by 2:
x = $0.10 / 2
x = $0.05
So, the price of the bookmark is $0.05.
To find the price of the book, we can substitute this value back into one of the earlier equations:
Price of the book = x + $10 = $0.05 + $10 = $10.05
Therefore, the price of the book is $10.05 and the price of the bookmark is $0.05.