3. For the three cubes shown below, determine their surface area, volume and surface area to volume ratio. Then, circle the one you believe would be the most efficient and write a summary stating why

To determine the surface area, volume, and surface area to volume ratio for the three cubes shown, we need to know the length of the sides of each cube. Let's assign them names for easier referencing: Cube A, Cube B, and Cube C.

1. Cube A:
If the length of each side of Cube A is given as "a", then:
- Surface Area = 6a^2
- Volume = a^3
- Surface Area to Volume Ratio = (6a^2) / (a^3) = 6/a

2. Cube B:
If the length of each side of Cube B is given as "b", then:
- Surface Area = 6b^2
- Volume = b^3
- Surface Area to Volume Ratio = (6b^2) / (b^3) = 6/b

3. Cube C:
If the length of each side of Cube C is given as "c", then:
- Surface Area = 6c^2
- Volume = c^3
- Surface Area to Volume Ratio = (6c^2) / (c^3) = 6/c

To determine the most efficient cube with the highest surface area to volume ratio, we need to compare their ratios.

Summary:
By comparing the surface area to volume ratios of all three cubes, we can identify the most efficient one. The cube with the highest surface area to volume ratio is the most efficient because it has the largest surface area compared to its volume. In this case, since the surface area to volume ratio for each cube is 6/a, 6/b, and 6/c respectively, the cube with the smallest side length (a, b, or c) will have the highest ratio. Hence, we need to identify the cube with the smallest side length and circle it as the most efficient one.