bananas cost twice as much as oranges.sue buys 10 bananas and 3 oranges.with the same amout of money,she could have bought 4 bananas and how many oranges?
2(10)+1(3)=23 money spent
2(4)+1(x)=23
x= 15 oranges
10(2)+3(1)=23 money spent
4(2)+X(1)=23
X= 15 oranges
Henry buys bananas and oranges for a soup Kitchen. He buys 10 pounds of bananas And Twice as many pounds of oranges as bananas. How many pounds of oranges does Henry buy
To solve this problem, let's use algebraic equations.
Let's assume the cost of one orange is "x" dollars. Since bananas cost twice as much as oranges, we can say that the cost of one banana is "2x" dollars.
According to the given information, Sue buys 10 bananas and 3 oranges. The total cost of 10 bananas and 3 oranges can be represented as:
10 * (2x) + 3 * x
Now, let's find the cost of 4 bananas. We'll assume that the cost of "y" oranges can be obtained with the same amount of money. So, the cost of 4 bananas and "y" oranges is:
4 * (2x) + y * x
According to the problem, the two expressions above should be equal, as Sue could have bought the same amount of items with the same money. So, we can write an equation:
10 * (2x) + 3 * x = 4 * (2x) + y * x
Now, let's solve for "y":
20x + 3x = 8x + yx
23x = 8x + yx
23x = 9x
To get rid of the "x" terms, we can divide both sides of the equation by "x":
23 = 9 + y
Subtract 9 from both sides of the equation:
y = 23 - 9
y = 14
Therefore, Sue could have bought 4 bananas and 14 oranges with the same amount of money.
Please note that I have assumed the cost of one orange as "x" to solve this problem. Actual prices may vary.